حلول التدريبات العملية الجاذبية - ديناميكا (دون الطاقة)
29. بב.22- ارتفاع أقمار الاتصالات.
القوة الوحيدة المؤثرة على القمر الاصطناعي هي قوة الجاذبية العامة.
نكتب معادلة الحركة الدائرية:
«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mstyle mathsize=¨20px¨»«msub»«mi mathvariant=¨bold¨ mathcolor=¨#0000FF¨»§#931;F«/mi»«mi mathvariant=¨bold¨ mathcolor=¨#0000FF¨»R«/mi»«/msub»«mo mathvariant=¨bold¨ mathcolor=¨#0000FF¨»=«/mo»«mi mathvariant=¨bold¨ mathcolor=¨#0000FF¨»m«/mi»«mo mathvariant=¨bold¨ mathcolor=¨#0000FF¨»§#183;«/mo»«msup»«mi mathvariant=¨bold¨ mathcolor=¨#0000FF¨»§#969;«/mi»«mn mathvariant=¨bold¨ mathcolor=¨#0000FF¨»2«/mn»«/msup»«mo mathvariant=¨bold¨ mathcolor=¨#0000FF¨»§#183;«/mo»«mi mathvariant=¨bold¨ mathcolor=¨#0000FF¨»R«/mi»«mspace linebreak=¨newline¨/»«mspace linebreak=¨newline¨/»«msub»«mi mathvariant=¨bold¨ mathcolor=¨#0000FF¨»F«/mi»«mi mathvariant=¨bold¨ mathcolor=¨#0000FF¨»g«/mi»«/msub»«mo mathvariant=¨bold¨ mathcolor=¨#0000FF¨»=«/mo»«mi mathvariant=¨bold¨ mathcolor=¨#0000FF¨»m«/mi»«mo mathvariant=¨bold¨ mathcolor=¨#0000FF¨»§#183;«/mo»«msup»«mi mathvariant=¨bold¨ mathcolor=¨#0000FF¨»§#969;«/mi»«mn mathvariant=¨bold¨ mathcolor=¨#0000FF¨»2«/mn»«/msup»«mo mathvariant=¨bold¨ mathcolor=¨#0000FF¨»§#183;«/mo»«mi mathvariant=¨bold¨ mathcolor=¨#0000FF¨»R«/mi»«mspace linebreak=¨newline¨/»«mspace linebreak=¨newline¨/»«mfrac mathcolor=¨#0000FF¨»«mrow»«mi mathvariant=¨bold¨»G«/mi»«mo mathvariant=¨bold¨»§#183;«/mo»«msub»«mi mathvariant=¨bold¨»M«/mi»«mi mathvariant=¨bold¨»E«/mi»«/msub»«mo mathvariant=¨bold¨»§#183;«/mo»«menclose notation=¨updiagonalstrike¨»«mi mathvariant=¨bold¨»m«/mi»«/menclose»«/mrow»«msup»«mi mathvariant=¨bold¨»R«/mi»«mn mathvariant=¨bold¨»2«/mn»«/msup»«/mfrac»«mo mathvariant=¨bold¨ mathcolor=¨#0000FF¨»=«/mo»«menclose mathcolor=¨#0000FF¨ notation=¨updiagonalstrike¨»«mi mathvariant=¨bold¨»m«/mi»«/menclose»«mo mathvariant=¨bold¨ mathcolor=¨#0000FF¨»§#183;«/mo»«msup»«mfrac mathcolor=¨#0000FF¨»«mrow»«mn mathvariant=¨bold¨»4«/mn»«mo mathvariant=¨bold¨»§#183;«/mo»«mi mathvariant=¨bold¨»§#960;«/mi»«/mrow»«msup»«mi mathvariant=¨bold¨»T«/mi»«mn mathvariant=¨bold¨»2«/mn»«/msup»«/mfrac»«mn mathvariant=¨bold¨ mathcolor=¨#0000FF¨»2«/mn»«/msup»«mo mathvariant=¨bold¨ mathcolor=¨#0000FF¨»§#183;«/mo»«mi mathvariant=¨bold¨ mathcolor=¨#0000FF¨»R«/mi»«mspace linebreak=¨newline¨/»«mspace linebreak=¨newline¨/»«mi mathvariant=¨bold¨ mathcolor=¨#0000FF¨»G«/mi»«mo mathvariant=¨bold¨ mathcolor=¨#0000FF¨»§#183;«/mo»«msub»«mi mathvariant=¨bold¨ mathcolor=¨#0000FF¨»M«/mi»«mi mathvariant=¨bold¨ mathcolor=¨#0000FF¨»E«/mi»«/msub»«mo mathvariant=¨bold¨ mathcolor=¨#0000FF¨»=«/mo»«msup»«mfrac mathcolor=¨#0000FF¨»«mrow»«mn mathvariant=¨bold¨»4«/mn»«mo mathvariant=¨bold¨»§#183;«/mo»«mi mathvariant=¨bold¨»§#960;«/mi»«/mrow»«msup»«mi mathvariant=¨bold¨»T«/mi»«mn mathvariant=¨bold¨»2«/mn»«/msup»«/mfrac»«mn mathvariant=¨bold¨ mathcolor=¨#0000FF¨»2«/mn»«/msup»«mo mathvariant=¨bold¨ mathcolor=¨#0000FF¨»§#183;«/mo»«msup»«mi mathvariant=¨bold¨ mathcolor=¨#0000FF¨»R«/mi»«mn mathvariant=¨bold¨ mathcolor=¨#0000FF¨»3«/mn»«/msup»«mspace linebreak=¨newline¨/»«mspace linebreak=¨newline¨/»«/mstyle»«/math»
نعبر عن نصف قطر مدار القمر الاصطناعي كمجموع نصف قطر الكرة الأرضية وارتفاع القمر الاصطناعي فوق سطح الأرض.
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نحسب ارتفاع القمر الاصطناعي بدلالة نصف قطر الكرة الأرضية وكتلتها.
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لذلك ، لكي تكون أقمار الاتصالات التي تتحرك حول الكرة الأرضية فوق نقطة ثابتة، يجب أن تتحرك على ارتفاع 35.84 مليون متر فوق سطح الأرض.