حلول التدريبات العملية الديناميكا لجسمين
9. جسم معلق وجسم آخر معلق على سطح مائل غير أملس
9.3. ايجاد النسبة بين الكتلتين
إذا كان الجسمان يتحركان بسرعة ثابتة، فهذا يعني أنهما يتحركان بتسارع 0.
سوف نستخدم تعبير التسارع الذي قمنا بتطويره:
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نعوّض a = 0:
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notation=¨updiagonalstrike¨»«msub»«mi mathvariant=¨bold¨»M«/mi»«mn mathvariant=¨bold¨»2«/mn»«/msub»«mi mathvariant=¨bold¨»g«/mi»«/menclose»«/mfrac»«mo mathvariant=¨bold¨ mathcolor=¨#0000FF¨»§#160;«/mo»«mo mathvariant=¨bold¨ mathcolor=¨#0000FF¨»=«/mo»«mo mathvariant=¨bold¨ mathcolor=¨#0000FF¨»§#160;«/mo»«mn mathvariant=¨bold¨ mathcolor=¨#0000FF¨»0«/mn»«mspace linebreak=¨newline¨/»«mspace linebreak=¨newline¨/»«mfrac mathcolor=¨#0000FF¨»«msub»«mi mathvariant=¨bold¨»M«/mi»«mn mathvariant=¨bold¨»1«/mn»«/msub»«msub»«mi mathvariant=¨bold¨»M«/mi»«mn mathvariant=¨bold¨»2«/mn»«/msub»«/mfrac»«mo mathvariant=¨bold¨ mathcolor=¨#0000FF¨»§#160;«/mo»«mo mathvariant=¨bold¨ mathcolor=¨#0000FF¨»-«/mo»«mo mathvariant=¨bold¨ mathcolor=¨#0000FF¨»§#160;«/mo»«mi mathvariant=¨bold¨ mathcolor=¨#0000FF¨»sin«/mi»«mo mathvariant=¨bold¨ mathcolor=¨#0000FF¨»(«/mo»«mi mathvariant=¨bold¨ mathcolor=¨#0000FF¨»§#945;«/mi»«mo mathvariant=¨bold¨ mathcolor=¨#0000FF¨»)«/mo»«mo mathvariant=¨bold¨ 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